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export type Data = { [key: string]: unknown } export type UnionToIntersection<U> = ( U extends any ? (k: U) => void : never ) extends (k: infer I) => void ? I : never // Conditional returns can enforce identical types. // See here: https://github.com/Microsoft/TypeScript/issues/27024#issuecomment-421529650 // prettier-ignore type Equal<Left, Right> = (<U>() => U extends Left ? 1 : 0) extends (<U>() => U extends Right ? 1 : 0) ? true : false; export type HasDefined<T> = Equal<T, unknown> extends true ? false : true // If the the type T accepts type "any", output type Y, otherwise output type N. // https://stackoverflow.com/questions/49927523/disallow-call-with-any/49928360#49928360 export type IfAny<T, Y, N> = 0 extends 1 & T ? Y : N export type LooseRequired<T> = { [P in string & keyof T]: T[P] }